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      1.95传奇私服发布网

      发布时间:2019-05-20 00:52

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      5,519 questions
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      传奇世界补丁下载

      I read lots of journal papers that had used Dual laplacian, but didn't find any theory. So plz help me witht dual laplcian and give some link for study materials Thanks
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      38 views

      私服传奇世界

      I know that the integral homology group of the manifold $M$ is given by $$ H_j(M,\mathbb{Z}) $$ I also have tried that $H_j(T^3,\mathbb{Z})$ is given by $$ H_0(T^3,\mathbb{Z})=\mathbb{Z}, $$ $$ H_1(...
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      2answers
      36 views

      找sf传奇网站

      I would like to understand the solution to the following Ode, can we solve that? This there any idea that we can analysis something on that? $\frac{d^2}{dx^2}u(x)+\sinh(u)=0$. Thanks.
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      33 views

      网通合击传奇

      The text I am using "Nonlinear PDEs - A Dynamical Systems Approach" (Hannes Uecker) defines a stable manifold as follows Definition : Let $u^*$ be a fixed point of the ODE $\dot{u} = f(u)$ with ...
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      14 views

      c传奇私服

      I'm reading the article "Local and simultaneous structural stability of certain diffeomorphisms - Marco Antônio Teixeira", and on the first page says "Denote $G^r$ the space of germs of involution at $...
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      1answer
      10 views

      新开网通sf

      I'm trying to do this problem: Let $f: S^2 \to \mathbb{R}^3$ given by $f(x,y,z)=z$. For the regular values $-1<t<1$, find the orientations of $f^{-1}(t).$ The hint is to find a positively ...
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      21 views

      好私服

      I am going through Guillemin and Pollack and have reached some difficulty with orientation. The way it does preimage orientations confuses me, and likewise the problems on the orientation of ...
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      0answers
      45 views

      1.85神龙合击

      Suppose I have a complex vector space with basis $\{v_1, ..., v_p, w_1, .., w_q\}$ and the standard Hermitian form of type $(p, q)$. I want to prove that the space $D$ of all the dimension $q$ sub-...
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      2answers
      54 views

      传奇外传攻略

      I have a doubt about the fact that a derivative of $f:M\to \mathbb R$ of a $\mathcal C^1$ manifold is well defined... Indeed, let $a\in M$ and $(U,\varphi )$ a chart from a $\mathbb C^1$ atlas s.t. $a\...
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      1answer
      33 views

      1.76网页版传奇

      The following question is stated on an exercise sheet of Riemannian Geometry. We look at the pseudo Riemannian metric, defined on $M = \mathbb{R}^2 \ 0 $ by \begin{align*} < \partial_x, \...
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      今日新开传世

      What are the (technical) differences between Sobolev spaces on domains $\Omega \subset \mathbb R^n$ or (compact) manifolds such as two-dimensional spheres?
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      3answers
      53 views

      超级变态网页传奇

      I am reading "Information Geometry and its Application" by Shun-ichi Amari. The example of a sphere as a 2-dimensional manifold says that, and I quote: A sphere is the surface of a three-...
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      1answer
      33 views

      新开变态传奇

      Every compact connected 2-manifold (I define this as a surface) is homeomorphic to a 2-sphere, a connected sum of tori or a connected sum of projective planes. Since the fundamental groups of the ...
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      84 views

      1.99传奇发布网

      My book is An Introduction to Manifolds by Loring W. Tu. Let $S = \{x^3-6xy+y^2=-108\}$, and let "submanifold" and "$k$-submanifold" mean, respectively, "regular" and "regular $k$-submanifold". As in ...
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      2answers
      223 views

      传奇私服开区预告

      My book is An Introduction to Manifolds by Loring W. Tu. As can be found in the following bullet points Can a topological manifold be non-connected and each component with different dimension? Is $[...
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      2answers
      27 views

      英雄合击私服发布网

      Let $SL(n,\Bbb{C})$ be the group of matrices of complex entries and determinant $1$. I want to prove that $SL(n,\Bbb{C})$ is a regular submanifold of $GL(n,\Bbb{C})$. An idea is to use the ...
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      1answer
      37 views

      盛大传奇官网

      My book is From Calculus to Cohomology by Ib Madsen and Jørgen Tornehave. As part of Proposition 11.13(i), I'm trying to compute the degree of the "interchanging" $T: J \times K \to K \times J, T(x,y)...
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      1answer
      11 views

      传奇私服客户端下载

      My book is From Calculus to Cohomology by Ib Madsen and Jørgen Tornehave. This is the definition of local index: Corollary 11.10 says if $f$ isn't surjective, then $\deg(f) = 0$, I guess by empty ...
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      1answer
      42 views

      复古传奇网站

      I know how to show this if $X$ and $Y$ are euclidean spaces using IFT but wanted to confirm proofs about the abstract case. Q) a) $X$, $Y$ are smooth manifolds and $f:X\rightarrow Y$ is smooth. Show ...
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      1answer
      29 views

      传奇合击版

      If $H$ is a closed subgroup of Lie group $G$, then show that $\mathfrak{h}=0$ if and only if $H$ is discrete, where $\mathfrak{h}$ is the Lie algebra of $H$. We know that $\mathfrak{h}=\{X\in \...
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      1answer
      22 views

      1.76传奇

      Is the subgroup $S=\{m+n\alpha|\;m,n\in \mathbb{Q}\}$, where $\alpha$ is a fixed irrational number, locally compact in $\mathbb{R}$ ? Approach: I can see that $S$ is dense in $\mathbb{R}$. But I am ...
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      1answer
      42 views

      新开热血传奇sf

      I want to use the technique from hatcher section 3.2 to compute the cup product structure of a punctured torus (with $\mathbb{Z}$ coefficient), but I found that I still don't know how to do this when ...
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      2answers
      98 views

      变态传奇合击

      Recently I have been reading a lot about $\mathbb{Z}_2$-actions on topological spaces. Mainly I was focused on surfaces such as the sphere, torus and Klein bottle and here the existence of a ...
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      33 views

      刚开一秒的传奇

      The definition of Differential Manifold or Smooth Manifold include $\text{Second countability}$ and $\text{Hausdorffness condition}$. My question is why we include Second countability and ...
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      2answers
      217 views

      好玩的传奇私服

      Suppose that we have a Riemannian metric $ds^2=Edu^2+2Fdudv+Gdv^2$ on a local coordinate neighborhood $(U;(u,v))$ prove that for the following vector fields: $$e_{1}=\frac{1}{\sqrt{E}}\frac{\partial}{...
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      1answer
      17 views

      天裂传奇私服

      I have a question about the manifold, especially when the manifold is as well a vector space of finite dimensional $k$. Actually, let $(v_1, \dots, v_k)$ be a basis of F as a vector space. I would ...
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      1answer
      145 views

      传奇私服平台

      The unit sphere $n$ dimensional is the set $$\mathbb{S}^n=\bigg\{(x_1,x_2,\dots, x_{n+1})\in\mathbb{R}^{n+1}\;|\;\big(x_1^2+x_2^2+\cdots+x_{n+1}^2\big)^{1/2}=1\bigg\}.$$ For all $i=1,\dots, n+1$ ...
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      33 views

      传世 私服

      Let $M$ be a smooth $n$-manifold and let $U\subseteq M$ be any open subset. Define an atlas on $U$ $$\mathcal{A}_{U}=\big\{\text{smooth charts}\;(V,\varphi)\;\text{for}\; M\;\text{such that}\;V\...
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      30 views

      传奇开服一条龙

      This is a problem from Lee 17.12: Suppose $M$ and $N$ are compact, oriented, smooth n-manifolds, and $F:M\rightarrow N$ is a smooth map. Prove that if $\int_M F^*\eta \neq 0$ for some $\eta \in \...
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      1answer
      120 views

      超级变态传奇私服

      I have a hard time seeing if the derivative of a vector field along a curve or parallel transport is the main purpose of introducing the connection on a vector bundle. Anyone have some idea about ...
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      32 views

      风云sf发布网

      I am self-learning integration on manifolds, and I'm trying to find an answer to the following question. For the manifold $M=\{(x,y) \in \mathbb{R} : (x,y) \neq (0,0) \}$, let $f: M \rightarrow \...
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      44 views

      传奇私服英雄合击版

      I am reading Munkres’ Analysis on Manifolds, and I am having trouble understanding the comment after the following statement. Let $A$ be an open set in $\mathbb{R}^k$; let $\eta$ be a $k$-form ...
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      38 views

      私服网

      Let $M$ be a compact smooth $3$-manifold, and $h: M\to \mathbb{R}$ a function such that $\{0\}$ is a regular value of $h$, and define $\Sigma = h^{-1}(0).$ Moreover, we will denote $\mathfrak{X}^r(M)$ ...
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      28 views

      新开热血传奇私服发布网

      The weak formulation of the Poisson equation of Dirichlet type in Euclidean space reads For given source function $f \in H^{-1}(\Omega)$ find $u \in H_0^1(\Omega)$ such that \begin{equation} \int_{\...
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      1answer
      20 views

      倚天传奇私服

      Munkres book on Manifolds constructs a wedge product by defining the following sum on $f$ (an alternating $k$-tensor on $V$) and $g$ (an alternating $l$-tensor on $V$): $$(f \wedge g)(v_1,...,v_{k+l}) ...
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      2answers
      35 views

      最新电信传奇私服

      I'm trying to prove that the universal cover of $S^1 \times S^2$ is $\mathbb{R}^3 \setminus \{0\}$. I know that the universal cover of $S^1$ is $\mathbb{R}$ and the universal cover of $S^2$ is $S^2 $. ...
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      1answer
      51 views

      精品辅助官网

      I’m having difficulty solving this problem. Could you tell me how to prove this? I showed the intersection with two variables, but still don’t see how to prove that it’s a manifold. ↓the problem and ...
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      1answer
      50 views

      传奇发服网

      In wikipedia there is a proof for 3-manifolds that I don't understand. It says that if $M$ is an irreducible manifold and we express $M=N_1\sharp N_2$, then $M$ is obtained by removing a ball each ...
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      22 views

      玫瑰大极品传奇

      Consider a smooth map $\Delta :M \to N$. Let $q\in N$ be a regular point. I want to understand how I go about examining the topology of $\Delta^{-1}\{q\}\subseteq M$. In the example of the sphere, $\...
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      5answers
      94 views

      传世2私服

      I know as a matter of fact, that $\mathbb{R}$ compactifies to a circle $S^1$. So there should, in my visualization, exist a single infinity. If I want to go from $S^1$ back to $\mathbb{R}$ I have to ...
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      14 views

      网通传奇jjj

      I just started studying Information Geometry and its applications by Amari. Right in the first chapter, the author talks about parallel transport in Dually flat manifolds. Just some quick notation: ...
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      1answer
      71 views

      私服客户端下载

      For each nonnegative integer $n$, the Euclidean space $\mathbb{R}^n$ is a smooth $n$-manifold with the smooth structure determined by the atlas $\mathcal{A}=(\mathbb{R}^n,\mathbb{1}_{\mathbb{R}^n})$. ...
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      1answer
      24 views

      变态热血传奇私服

      Denote $x = (x_1,...,x_n)$. I'm trying to prove the following: $$\int_{S^{n-1}}x_1^2dS =\int_{S^{n-1}}x_k^2dS \; , \; 2\leq k\leq n $$ Intuitively this equality is due to the symmetry of the ...
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      47 views

      传世私服发布网

      Why does the Jacobian have constant sign for connected sets? I've seen in two separate proofs now (having to do with manifold orientation) that the Jacobian has constant sign for a connected set, but ...
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      0answers
      30 views

      盛大传奇3官网

      Let $X$ be a (smooth) vector field on a manifold $M$ and let $\gamma$ be its integral curve passing through $m$ at $t=0$ and finally let $T:U\times (-c,c)\to M$ be the local group of transformations ...
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      1answer
      29 views

      新开合击传奇sf

      Denote $\mathbb{R}^0=\{0\}$. Proposition. A topological space $M$ is a $0$-manifold if and only if it is a countable discrete space. Proof. $(\Rightarrow)$ Suppose that $M$ be a topological ...
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      1answer
      67 views

      传奇世界2私服

      I was trying to understand the definition of a manifold. This question arised: is every manifold $M$ the inverse image of some $\Delta : \mathbb{R}^n \to \mathbb{R}$. The implicit function theorem, i ...
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      2answers
      100 views

      网通传奇

      The Classification Theorem for surfaces says that a compact connected surface $M$ is homeomorphic to $$S^2\# (\#_{g}T^2)\# (\#_{b} D^2)\# (\#_{c} \mathbb{R}P^2),$$ so $g$ is the genus of the surface, $...
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      votes
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      40 views

      超级变态65535

      I'm currently working through Do Carmo's book Riemannian Geometry and came across the following question: Let $M$ be a Riemannian manifold with the following property: given any two points $p, q \in ...
      2
      votes
      1answer
      52 views

      纯网通传奇

      Let $H$ be a genus $g$ handlebody embedded in $S^4$ and let $X = S^4 - N(\partial H)$ where $N(\partial H)$ is an open tubular neighborhood of the boundary of $H$. What is $X$? In the case where $g=...

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